Published by:
CGP EDU Academic Team
Published on: August 14, 2026
A graph between log t 1/2 and log a (abscissa) 'a' being the initial conc. of A in the reaction.
A → product, the rate law is -
A
– 
= k[A] 0
= k[A] 0
B
– 
= k[A]
= k[A]
C
– 
= k[A] 2
= k[A] 2
D
None of these
Text Solution
Verified by ExpertsThe correct answer is:
C
t 1/2 = k a (1–n)
log t 1/2 = log k + (1 – n) log a
∴ 1 – n = 1
n = 2
∴ second order reaction
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